| Urdhva-tiryagbhyam
or "vertically and cross-wise"
1. 31 X 12
Multiply vertically on the left: 3 x 1 = 3
(first figure)
Multiply cross-wise and add: (3 x 2) + (1 x 1) = 7
(middle figure)
Multiply vertically on the right 2 x 1 = 2
(last figure)
So the answer is 372
2. 275 x 513
Multiply
vertically 5 x 3 =15 write 5 and carry 1 ==>
5
Multiply
and add crosswise last two digits (3x7)+(1x5) = 26+ carry 1
=27
write
7 and carry 2 ==> 75
Multiply
and add vertically and cross wise all digits
(2x3)
+ (5x5) + (7x1)=38+ carry 2 = 40 write 0 and carry 4 ==>075
Multiply
and add crosswise first two digits (1x2)+(5x7)=37+ carry 4=41
write
1 and carry 4 ==> 1075
Multiply
vertically 2x5=10 + carry 4 ==> 14
write
141075
So
275x513 = 141075
3. Divide (12X2 –8X-32) by (X-2) using Urdhva-Tiryak
The quotient can be written as (12X+k)
We also know that –8x = kx - 24x Hence k = 16 cross-check
–2k = -32 third term
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Some
rules of thumb
1.
Multiplying a number by 11
To multiply any two digit number by 11 we just put the total of the
two figures between the 2 digits.
36 x 11 = 3 (3+6) 6 = 396
74 x 11 = 7 (7+4) 4 = 7+carry 1 (1) 4 = 814
234 x 11 = 2 (2+3) (3+4)
4 = 2574
2.
Diving by 9.
23 / 9 = 2 remainder 5
The first digit of 23 i.e, 2 is the answer and remainder is
sum of 2 and 3!
134 / 9 = 14 remainder 8
Answer is (1st digit of 134)(1+3) remainder (1+3+4)
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